Refer to image: http://session.masteringphysics.com/problemAsset/1…
In this problem, you must express the angle (alpha) in the above equation in terms of (theta), (phi), and/or (pi) when entering your answers.
A. What is the torque (rA) about axis A due to the force (Fvector)?Express the torque about axis A at Cartesian coordinates (0,0). rA = ???
B. What is the torque rB about axis B due to the force Fvector? (B is the point at Cartesian coordinates (0,b), located a distance b from the origin along the y axis.) Express the torque about axis B in terms of F, theta, phi, pi, and/or other given coordinate data.
C. What is the torque rC about axis C due to Fvector? (C is the point at Cartesian coordinates (c,0), a distance c along the x axis.) Express the torque about axis C in terms of F, theta, phi, pi, and/or other given coordinate data.
What is the torque about axis D due to ? Aswer same as the previous problems.
Thank you for your help!
3 Answers
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any torq is vector t=[r×F], where vector r is arm, vector F is force;
our F=|F|*(cos(θ), sin(θ), 0); A♠ r=0; t=0;
B♣ r=(0, -b, 0); t/|F|=
│
ij│
<code> -b</code><code> </code>“0│ = (0, 0, bcos(θ)); |t| =|Fb*cos(θ)|;│ cos(θ), sin(θ), 0│
C♣ r=(-c, 0, 0); t/|F|=
│
<code>j</code><code> </code></code><code> </code>k││
<code>-c</code></code><code> </code><code>0</code>│ cos(θ), sin(θ), 0│
D♣ r=(-dcos(φ), -dsin(φ), 0); t/|F|=
│
<code>j</code><code> </code></code><code> </code><code> </code>``k││-dcos(φ), -dsin(φ), 0│ = (0, 0, -dcos(φ)sin(θ) + dsin(φ)cos(θ))=
│ cos(θ),
sin(θ),= (0, 0, dsin(φ-θ))=; |t| =|Fd*sin(φ-θ)|;
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Finding Torque Mastering Physics
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Part A) 0
Part B) bFcos(θ)
Part C) -cFsin(θ)
Part D) d*F*(φ-θ)
Source(s): Another Mastering Physics victim
