A 1.50m -long, 550g rope pulls a 7.00kg block of ice across a horizontal, frictionless surface. Physics Help?

NetherCraft 0

A 1.50m long, 550g rope pulls a 7.00kg block of ice across a horizontal, frictionless surface. The block accelerates at 2.20m/s2 . How much force pulls forward on (a) the ice, (b) the rope?

3 Answers

  • Rope Pulls

  • The ice accelerates @ 2.2m/s^2. It has a mass of 7 kg. F = ma

    F = 7 kg x 2.2 m/s^2 = 15.4 N.

    The ice / rope “system” has a mass of 7.55 kg. It is also accelerating at a rate of 2.2 m/s^2.

    F = 7.55 kg x 2.2 m/s^2 = 16.61 N

  • solution;

    mass of rope m=550g=0.55

    mass of block mb =7 kg

    acceleration produced by

    block a=2.2m/s^2

    now according to the formula

    f=ma

    =7*2.2

    =15.4N

    and, acceleration produced by rope means acceleration produced by block;

    f=ma =[0.55+7]*2.2=16.61N

    HENCE 15.4N force pulls forward the ice and 16.61N force to the rope

    Source(s): THANK YOU>>>>>>>

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