A beam of electrons is accelerated through a potential difference of 10 kV before entering a region having uniform electric and magnetic fields that are perpendicular to each other and perpendicular to the direction in which the electron is moving. If the magnetic field in this region has a value of 0.010 T, what magnitude of the electric field is required if the particles are to be undeflected as they pass through the region?
A beam of electrons is accelerated through a potential difference of 10 kV before entering a region having uniform electric and magnetic fields that are perpendicular to each other and perpendicular to the direction in which the electron is moving. If the magnetic field in this region has a value of 0.010 T, what magnitude of the electric field is required if the particles are to be undeflected as they pass through the region?
2.3 × 103 V/m
5.9 × 105 V/m
7.2 × 106 V/m
6.0 × 105 V/m
7.9 × 103 V/m
2 Answers
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You know that V=E/Q
10000*(1.60*10^-19)=E
E=1.6*10^-15 J
This Energy will convert to Kinetic energy as beam of electron is in motion.
1/2mv^2=1.6*10^-15
0.5*(9.11*10^-31)v^2=1.60*10^-15
v=5.9*10^7 ms^-1
Now u got the velocity,..
U know that E=BV
E=0.010*5.9*10^7
E=5.9*10^5 Vm^-1…
Hope i helped….
Peace upon u…
Source(s): Allah I love u..(The All Knowing) -
this is trivial The electron features 10,000 Joules consistent with coulomb. because of the fact it has a fee of a million.6 . 10^–19 C it might have won a million.6 . 10^–19 . 10^4 = a million.6 . 10^–15 J this is the respond, to 2 sig figs. Now you do a tiny little bit of artwork and write it out in despite the fact that format you choose on your answer application.
