# A gun with a muzzle velocity of 100 m/s is fired horizontally from a tower. Neglecting air resistance, how far

0

A gun with a muzzle velocity of 100 m/s is fired horizontally from a tower. Neglecting air resistance, how far downrange will the bullet be 1 second later?

a. 100

b. 490

c. 98

d. 50 m

e. none of these

• a). 100m.

When the gun is fired and the bullet leaves the gun, there will be two forces acting on the bullet: the forward force and gravity.

The force from the gun will cause the bullet to move forward, and gravity will cause it to move down towards the ground.

So the gun force will cause the bullet to move forward by 100m and gravity will cause the bullet to drop by 9∙81 meters.

The total distance traveled by the bullet will be 100∙48..m.

• Theoretically they are going to it the floor together; the vertical portion of air resistance is an same no matter if this is a function of vertical speed. yet air resistance isn’t that straightforward. this is non-linear, has vortices, and modeling issues. The intense horizontal air resistance would carry over to the vertical and so the 2d ball would hit first. i do not recognize. Why do not you bypass up a 175m tower with a cannon and a couple of balls and enable us recognize the right result?

• Assuming the bullet does not hit the ground or anything else, 100 meters, (a)

• e. none of these

Because the vertical movement (due to gravity) is independent of the horizontal movement.

d = 1/2 a t^2

so after 1 second d = 5 m. (approx)

• I believe you need to know how tall the tower is.

Also Check This  How do you delete your Rhapsody account?