A hockey puck is given an initial speed of 16m/s .?

4 Answers

• There is only only force, friction. By Newton’s 2nd Law we have ug=a so will need to find the acceleration (deceleration) which from kinematics we find is a=v^2/2s=2.13m/s^2. The coefficient of kinetic friction is u=a/g=0.217

• As a “Puck bunny” – I really feel the need to answer, since there is a strange breed of them that make us look bad! 😉 Some of us Puck bunnies just really love hockey. 1. Who is smarter: Definatley a puck bunny! 2. Is there such a thing as an old puck bunny? Yes there is! You’d be surprised. Any ladies losing sleep over Chelios? Nope! 3. Not that I have seen, although I have heard of puck bunny’s contracting “something” from some dirty players.. 4. Nope, groupies are a breed of their own (and they scare me!). Gold diggers are from the same species as those “bad” puck bunnies. 5. Not usually, but we have been known to be tattooed. 6. We like them all for different reasons. 7. Yes they do, and I have actually seen them! 8. We train in the off season, and attend football games 😉

• Coeff. of Kinetic Friction= Kinetic Friction/Normal Force

  We know

  u= 16 m/s, s= 60 m, m= M, v= 0, Normal Force= 9.81M

  We want

  a=?, Kinetic Friction

  …………

  –Solution–

  Using

  2as = v^2 – u^2

  a= 0-256/120

  a= 2.14 ms^2 (the negative is for retardation, we can ignore it)

  Now.

  F=ma

  F(Friction)=2.14M

  Now using the formula stated first we have,

  Coeff of Kinetic Friction: 2.14M/9.81M (M cancels off 😉 )

  Therefore the answer is: 0.05, quite slippery surface…

• I believe the answer is off a bit. it should be 0.5 instead…