A particle moves along the *x* axis according to the

equation x = 2.07 + 2.91t − 1.00t^{2},

where *x* is in meters and *t* is in seconds.

(a) Find the position of the particle at *t* = 3.30

s.

(b) Find its velocity at *t* = 3.30 s.

(c) Find its acceleration at *t* = 3.30 s.

## Answer

0 X = 2.07 + 2.91 € – 1:00+ at t = 3.305 x = 2.07 + 2.91 x 3.3 – 1 X (3-372 M x = 0.783 m velocity of partide V = dx dt No 0+ 2.91 2t at to 3.35 v = 2.91 2 x 3.3 mis V -3.69 m/s acceleration of barticle Q = dv dt a = 0 – 2 m/s2 az -2 m/s ?