# A person scuffing her feet on a wool rug on a dry day accumulates a net charge of -93μC .How many excess elect?

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A person scuffing her feet on a wool rug on a dry day accumulates a net charge of -93μC .How many excess electrons does she get?

By how much does her mass increase?

• For physics problems, it’s best to start off by listing everything that’s given:

Net charge (Q) = -93 μC

Although not given, the following info should be known:

mass of electron (me) = 9.1 x 10^-31 kg

charge of electron (q) = -1.6 x 10^-19 C

For the first question:

The number of electrons (N) equals the total charge divided by the charge per electron:

N = Q/q = (-93)(10^-6) / (-1.6)(10^-19)

N = 5.8 x 10^14 electrons

Second question:

If the she has 5.8 x 10^14 excess electrons, then her mass increases by the mass per electron times each of the excess electrons:

In other words:

Increase in the mass of lady

= N(me)

= (5.8)(10^14)(9.1)(10^-31)

= 5.3 x 10^-16 kg

Hope I helped..

• Scuffing

• elementary charge = 1.60217657 × 10-13 μC

93μC / 1.60217657 × 10-13 μC/electron = 58.05 x 10^13 electrons

9.10938291×10−31 kg/electron * 58.05 x 10^13 electrons = 5.29 x 10^-16 kg

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