touch. The small wheel has a radius of 2.0 cm and accelerates at the rate of 7.2 rad/s^2 and it is in contact with the pottery wheel (radius 25.0 cm). Calculate a) the angular acceleration of the pottery wheel and b) the time it takes the pottery wheel to reach its required speed of 65 rpm.
3 Answers
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First you must find the tangential acceleration of the outer most point on the small wheel. This is equal to the angular acceleration times the radius.
a = r*(angular acceleration) = 2(7.2) = 14.4 cm/s^s
This is equal to the tangential acceleration of the outer most point on the large wheel because they are in contact and not slipping. So the to find the angular acceleration of the large wheel, you divide the tangential acceleration by the radius.
angular acceleration = a/r = 14.4/25 = 0.576 rad/s^2
To find the time it takes the large wheel to reach 65 rpm you must first convert it to rad/s
(65rev / 1min)(2pi rad / 1rev)(1min / 60sec) = 6.8068 rad/s
The angular acceleration multiplied by time will give you the angular velocity.
angular acceleration * (t) = angular velocity
0.576t= 6.8068
t = 6.8068/0.576
t = 11.82 seconds (approximately)
You might want to check my calculations to be sure on the values.
I hope this helps
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Pottery Wheel Used
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RE:
A small rubber wheel is used to drive a lage pottery wheel, and they are mounted so that their circular edges?
touch. The small wheel has a radius of 2.0 cm and accelerates at the rate of 7.2 rad/s^2 and it is in contact with the pottery wheel (radius 25.0 cm). Calculate a) the angular acceleration of the pottery wheel and b) the time it takes the pottery wheel to reach its required speed of 65 rpm.
