Home / Questions / An electrical motor spins at a constant 2695.0 rpm. If the armature radius is 7.165 cm, what is the acceleration of the edge of the rotor?

An electrical motor spins at a constant 2695.0 rpm. If the armature radius is 7.165 cm, what is the acceleration of the edge of the rotor?

NetherCraft

Questions

November 19, 2022 0

A) 28.20 m/s^2

B) 572,400 m/s^2

C) 281.6 m/s^2

D) 5707 m/s^2

please show me how to get answer

1 Answer

Angular-speed, w = 2695 rpm = 2695*2pi/60 = 282.22 rad/sec,

Radius, r = 7.165 cm = 0.07165 meters,

So,

linear-velocity, v = rw = 0.07165*282.22 = 20.22 m/sec,

Hence,

Acceleration, a = v^2/r = (20.22)^2/0.07165 = 5706.78 m/s^2 >========< ANSER