An electron and a proton are fixed at a separation distance of 881 nm. Find the magnitude of the electric field at their midpoint.
Magnitude: Please answer in N/C. Thank you! 🙂
1 Answer
-
At the midpoint, the electric field direction due to the electron is toward it.
The electric field direction due to the proton is also toward the electron.
E = k(2e)/(d/2)²
E = 8ke / d²
E = 8(8.99e9 N-m²/C²)(1.609e-19 C) / (8.81e-7 m)²
E = 1.49e4 N/C
