An ion’s position vector is initially r= (1.1 m)i + (-9.1 m)j + (-8.5 m)k, and 7.2 s later it is?

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r= (-8.5 m)i + (-8.2 m)j+ (9.2 m)k. In unit-vector notation, what is its average velocity during the 7.2 s?

2 Answers

  • v(avg) = (rf – ri)/7.2s …

    So v(avg) = (-8.5 – 1.1)/7.2i +(-8.2 – -9.1)/7.2j + (9.2 – -8.5)/7.2

    = -1.33i + 0.125j + 2.46k

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