The following five beakers, each containing a solution of sodium chloride (, also known as table salt), were found on a lab shelf:
Beaker Contents
1 200. ML of 1.50 solution M NaCl
2 100.ML of 3.00 m NaCl solution
3 150.ML of solution containing 19.5 of NaCl
4 100.ML of solution containing 19.5 of NaCl
5 300. of solution containing mol NaCl
1 2 3 4 5
most concentrated least concentrated
19.5 g
sorry
3 Answers

There is a problem in the given for #5. —300 ml ? and one mole of NaCL?
In any case, to solve this find the number of moles for each one and calculate the MOLARITY.
For #1, it is already given as 1.5 M
For #2, assuming it is 3.00 moles of the salt, then the molarity is 30 M, a large value.
For #3, convert 19.5 grams to moles which is approximately 0.333 moles. Divide this by the volume you get 2.22 M
For #4, same as #3 but use .100 L for volume and you get 3.33 M
For #5, assuming 300 mL and 1 mole of salt, then it is also 3.33 M
Thus the order is 2 > 4 = 5 > 3 >1.
You may need to clarify #5.

4,2,3,5=1

19.5… grams or moles or Molar?