A sample of steam with a mass of 0.527 g and at a temperature of 100 ∘C condenses into an insulated container holding 4.45 g of water at 6.0 ∘C.( ΔH∘vap=40.7 kJ/mol, Cwater=4.18 J/g⋅∘C)
1 Answer
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40,700(1mole/18g)(0.527g) + (0.527)(4.18)(100-x) = (4.45)(4.18)(x-6.0)
… solve for x
x = 73.23 C
