A weather balloon is inflated to a volume of 25.3 L at a pressure of 753 mmHg and a temperature of 23.1 degrees celcius. The balloon rises in the atmosphere to an altitude, where the pressure is 385 mmHg and the temperature is 16.2 degrees celcius.
1 Answer

p1 = 753 /760 = 0.991 atm
V1 = 25.3 L
T1 = 23.1 + 273.15 = 296.25 K
p2 = 385 /760= 0.507 atm
V2 = ?
T2 = 273.15 – 16.2 = 256.95
0.991 x 25.3/ 296.25 = 0.507 V2/ 256.95
V2 = 42.9 L