Calculate the molality of 6.0 M H2SO4 solution. The density of
the solution is 1.34 g/mL.
1. 4.48 m
2. 7.98 m
3. 8.10 m
4. 8.43 m
5. 10.2 m
Do i use moles/ Volume….. ?
2 Answers
-
the mass of 6.0 moles of H2SO4 is 6*(2*1+32+4*16) =6*98=588g
if the solution as a density of 1.35g/mL , then a litter weighs 1.34*1000=1340g
in this litter you have H2SO4 and water. The mass of water is 1340-588=752g =0.752kg
molality is nummber of moles of solute by kg solvent
so molality is 6/.752=7.98 moles of H2SO4 by kg water
-
Hmm not my string suit
Source(s): ☺ χαηζ ☻