Calculate the standard entropy change for the reaction 2Na(s)+Cl2(g)→2NaCl(s)?

NetherCraft 0

using the data from the following table:

Substance ΔH∘f (kJ/mol) ΔG∘f (kJ/mol) S∘ [J/(K⋅mol)]

Na(s) 0.00 0.00 51.30

Cl2(g) 0.00 0.00 223.1

NaCl(s) -411.0 -384.0 72.10

Express your answer to four significant figures and include the appropriate units.

2 Answers

  • Standard Entropy Table

  • Hi There!

    So what you do is ΔS∘=S∘(products)−S∘(reactants)

    so you take the product and multiple it by the coefficient. You do the same to the product. So it becomes.

    2 x 72.10- (2x 51.30 + 233.1)

    = 144.2-325.7

    = -181.5 J/K

    Hope this helps!

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