0

suppose the parabola has a vertex (4,-6) and also passes through the point (5,-4). write the equation of the parabola in vertex form

• y = a(x – 4)² – 6

=> -4 = a(5 – 4)² – 6

=> -4 = a – 6

i.e. a = 2

so, y = 2(x – 4)² – 6

:)>

• You are not dumb. Dumb means you cannot talk.

You are bright enough to ask for help. I call that SMART.

Y = A(X – H)Â² + K

Vertex = (H , K) = (4 , -6)…………H = 4 and K = – 6

Point is (X , Y) = (5 , -4)…………X = 5 and Y = – 4

Now solve for A by substituting in the values of H , K , X , Y

– 4 = A(5 – 4)Â² – 6

+6……………….+6

2 = A(1)Â²

A = 2

For the final answer replace A , H , K into the original equation

Y = 2(X – 4)Â² – 6………………ANSWER

Let me know if you have questions on this problem or any other math problems.

I am an excellent math teacher/tutor specializing in making students

faster…..smarter……and better looking like myself. Okay, just faster and smarter

….you don’t want to look like me. I TUTOR FREE ONLINE VIA SKYPE.

Keeps me busy since moving from Florida to France. I make C, D , F students

into A, B , C students. I make great students even greater.

If interested just let me know how to get in touch. If not that is fine also.

Mathcerely,

Robert Jones

“Teacher of Fine Students”

• 2(x-4)^2 -6

• Im sorry, idont knoww the answer to your question, but i just had to comment on your DP pic…omg, jenna marbles LUV HER!!

Also Check This  How much energy is required to heat 87.1 g acetone (molar mass=58.08 g/mol) from a solid at -154.0°C to a liquid at -42.0°C?