Consider the combination of resistors shown in the figure below.
http://www.webassign.net/sercp8/18p006.gif
(a) Find the equivalent resistance between point a and b.
the answer i got is 11.7Ω which is correct. but i cannot find the answers to the next questions.
(b) If a voltage of 26.8 V is applied between points a and b, find the current in each resistor.
12 Ω = ____
6 Ω = _____
5 Ω = _____
4 Ω = _____
8 Ω = _____
1 Answer

Solution can given using the ohm’s law.
The easiest part is finding current of 5Ω resistor.
I = U / R <=> I = 26.8 / 11.7 <=> I = 2.3A (assuming 11.7 is correct)
Then find total resistance of first 2 parallel resistors.
1/R = 1/R1 + 1/R2 <=> 1/R = 1/12 + 1/6 <=> 1/R = 0.083 + 0.16 <=> 1/R = 0.250 <=> R = 4
Then find voltage on them (which off course is the same on both of them)
We know total current is 2.3A so voltage is:
U = I * R <=> U =2.3 * 4 <=> U = 9.2
So current on 12Ω is:
I = U / R <=> I = 9.2 / 12 <=> 0.77A
And current on 6Ω is:
I = U / R <=> I = 9.2 / 6 <=> 1.53A
In the same manner you can calculate for 4Ω and 8Ω .
For simplicity reasons I have cutout some decimal points.