# Consider the combination of resistors shown in the figure below.?

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Consider the combination of resistors shown in the figure below.

http://www.webassign.net/sercp8/18-p-006.gif

(a) Find the equivalent resistance between point a and b.

the answer i got is 11.7Ω which is correct. but i cannot find the answers to the next questions.

(b) If a voltage of 26.8 V is applied between points a and b, find the current in each resistor.

12 Ω = ____

6 Ω = _____

5 Ω = _____

4 Ω = _____

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8 Ω = _____

• Solution can given using the ohm’s law.

The easiest part is finding current of 5Ω resistor.

I = U / R <=> I = 26.8 / 11.7 <=> I = 2.3A (assuming 11.7 is correct)

Then find total resistance of first 2 parallel resistors.

1/R = 1/R1 + 1/R2 <=> 1/R = 1/12 + 1/6 <=> 1/R = 0.083 + 0.16 <=> 1/R = 0.250 <=> R = 4

Then find voltage on them (which off course is the same on both of them)

We know total current is 2.3A so voltage is:

U = I * R <=> U =2.3 * 4 <=> U = 9.2

So current on 12Ω is:

I = U / R <=> I = 9.2 / 12 <=> 0.77A

And current on 6Ω is:

I = U / R <=> I = 9.2 / 6 <=> 1.53A

In the same manner you can calculate for 4Ω and 8Ω .

For simplicity reasons I have cutout some decimal points.