Consider the reaction 3 CH4(g) → C3H8(g) + 2 H2(g).?

NetherCraft 0

Calculate ΔG at 298 K if the reaction mixture consists of 50.0 atm of CH4, 0.0150 atm of C3H8(g), and 0.0120 atm of H2.

1 Answer

  • ΔG∘ = -RTln(K)

    3 CH4(g) → C3H8(g) + 2 H2(g)

    Kp = pC3H8(g) *pH2^2 / pCH4(g) ^3

    = 0.0150 0.0120 ^2 / 50 ^3 = 1.728 10^-11

    ΔG = 8.3144598 ×10−3 kJ  K−1 mol−1 298 K ln ( 1.728 10^-11)

    =ΔG = 61.40 kJ mol−1

Also Check This  What does the expression “she’s a trip” mean? Is it positive or negative?

Leave a Reply

Your email address will not be published. Required fields are marked *