Calculate ΔGrxn under these conditions:
PH2S= 2.01 atm
PSO2= 1.46 atm
PH2O=0.0126 atm
Is the reaction more or less spontaneous under these conditions than under standard conditions?
1 Answer
-
ΔGrxn = ΔG∘rxn + RT ln PH2O^2 / PH2S^2 PSO2
ΔGrxn = -102 kJ + (8.314 J/molK) (298K) ln (0.0126)^2 / (2.01)^2(1.46) = -128 kJ
