conjugate acid? A HC2H3O2(aq)
D. C2H3O2 to the negative
E. two of these
H3O+. H2O acts as a base on the left side of the equation, and its pair is H3O+. If the reaction were reversed the H3O+ would be the proton donor, making it the conjugate acid.
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CH3COOH is the conjugate acid to CH3COO-, which is therefore its conjugate base.
H3O+ is the conjugate acid to H2O