Also, calculate pressure against the side. Dimensions of a swimming pool are 28.0m by 8.5m and its uniform depth is 2.9m . The atmospheric pressure is 1.013×10^5N/m2.
With all due respect, this is yahoo answers, not yahoo suggestions.
The absolute PRESSURE at the bottom is atmospheric pressure + (1,000 x g x 2.9).
This is distinct from absolute FORCE on the bottom, which is pressure x area. Hope you are asking for the right thing.
Atmospheric pressure = 101,325Pa at STP.
Water density = 1,000kg/m^3., g is 9.8.
(1,000 x 9.8 x 2.9) = 28,420Pa.
(28,420 + 101,325) = 129,745Pa., or 129.745kPa., at the bottom of the pool.
The MEAN pressure against the side is 1/2 that, or 64.8725kPa.Source(s): Don’t worry about “Lisa”. She’s planting that same irrelevant answer to every question since joining 20th. March. She will be locked out in time. Hope she reads this, but probably won’t.