Find an expression for the bullet’s speed.?

NetherCraft 0

A bullet of mass m is fired into a block of mass M that is at rest. The block, with the bullet embedded, slides distance d across a horizontal surface. The coefficient of kinetic friction is mu_k_ .

Find an expression for the bullet’s speed Vbullet

useing the variables: d mu_k_ m M

I tried doing K = Friction * distance

1/2 mv ^2 = mu k * Msys * g * d and solved for V, isnt corret tho =/

Nevermind!!

I figured it out

Vi = ((M+m) * Sqr(uk*g*d))/m

2 before the uk in that

3 Answers

  • (K + U)initial – NC = (K + U)final, NC being non-conservative forces. μ is kinetic friction

    initially, K = mv^2/2 and U = 0, NC = (m + M)gμ

    finally, K = 0 and U = 0

    mv^2/2 + 0 – (m + M)gμ = 0 + 0

    mv^2 = 2(m + M)gμ

    v^2 = (2(m + M)gμ) / m

    v = √[(2(m + M)gμ) / m]

  • vi = ((M+m)*(sqrt(2*muk*g*d)))/m


Leave a Reply

Your email address will not be published.