I know that it’s in Quadrant II and I know to change cotx to cosx/sin x and set it to equal to -2. What do I do next? How will I know what negative number cos is in order to solve this problem?
Could you please show me the steps to solve this problem? Please leave the answer in fraction form.
1 Answer
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csc²(θ) = cot²(θ) + 1
csc²(θ) = (-2)² + 1
csc²(θ) = 5
sin²(θ) = 1/5
sin(θ) = √(5)/5 … It is positive, because, as you say, θ is in the second quadrant.
