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I am having such a hard time starting this. I know we use kirchoff’s law but I just keep second guessing if I am setting up the problem right!
Can anyone at least help me start? I’m not really looking to find a final answer(would be nice but i can live without it), but I am most looking to understand how to do it (cause I expect this sort of stuff on my exam coming up)!
Thanks for any help guys!
1 Answer
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“a ‘ be the current through 2 Ω from left to right an b be the current through 8 Ω so that the current through 4 Ω is ( a +b)
Considering the potential equations
in the left loop
6a +4 b = 9
In the left loop
12b + 4a = 15
a = 0.86 A and b = 0.96 A and a + b = 1.82 A
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Explanations;
The assumed current a passes through both 2 Ω and 4 Ω, the sum of the potentials
= 6 a .
The assumed current meets the negative of the 6 V and 3V battery hence the potential is – 6V – 3V = – 9V
The sum must be zero
6a +4 b -9 = 0
Similar explanation is for the other loop.
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