3 Answers

8
Let x = the first integer
Then x+1 = the second integer
And x+(x+1)>16.
Solve the inequality:
2x+1 > 16
2x > 15
x > 15/2
Since x is an integerâ€¦
x = 8

x = integer
x + 1 = next consecutive integer
x + x + 1 > 16
2x + 1 > 16
2x > 15
x > 7.5
least integer x can be is 8

x+(x+1) = 2x+1 >= 17
2x >= 16
x>= 8
the smaller of the two is at least 8