find the value of p in the quadratic equation p^2+13p-30=0?

6 Answers

  • p^2+13p-30=0

    for this the first thing you gotta do is to FACTORISE:

    so,

    (p + 15)(p – 2) = 0

    from the equation above you can deduce that:

    p + 15 = 0

    or,

    p – 2 = 0

    therefore, p = -15 or 2.

    as simple as that. good luck and have fun with math!

  • p^2 + 13p – 30 = (p + 15)(p – 2)

    p = -15 or 2

  • -15 and +2 …

    here’s how to solve it:

    1st, you have to factor them out (i find this easiest for this type of equation; there are other two ways: completing the square and quadratic formula), so the new equation looks like this:

    (p+15)(p-2)=0

    then, to solve for p, let p+15=0 and p-2=0, since the two factors are under a multiplication operation, and 0 multiplied by anthing will be equal to 0.

    so, the p=-15 and p=2 …

  • 2 ^ 2 + 13 x 2 – 30 = 0

    p = 2

  • p=*square root sign over30/13 divided by 2

  • (p+15)(p-2)=0

    so p=-15 or 2

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