Find the value of x. Round to the nearest degree.?

0

I need help solving this problem

(I had a diagram with this picture but i can not post the pic of the diagram so i described it below)

The Hypotenuse is 9

The Opposite Side (I do not have the lenght)

x is the angle between the hypotenuse and opposite right above the right angle

Solve for x

• You could just use the sine rule for this:

(a / Sin A) = (b / Sin B) = (c / Sin C)

Let little a = the hypotenuse. Then capital A is the angle between the adjacent and opposite (90 degrees). So:

a / Sin A = 9 / Sin 90

= 9 / 1

= 9

Therefore b / Sin B = 9. Let little b = the adjacent. Then capital B is the angle between the opposite and hypotenuse (i.e. the angle we want to find). So:

b / Sin B = 9

Sin B = b / 9

= 7/9

B = arcsin (7/9)

= 51.06 degrees

= 51 degrees (to nearest degree)

• You’re contradicting yourself ! the “Opposite ” is the side opposite the angle , you appear to want to use Adjacent to mean Opposite. To clarify what I mean, sketch a right-anbled triangle, with the right angle on the right end of the base. If x is the angle “above” the right angle, then the Opposite is the base, and the Adjacent is the upright side – the word Adjacent means “beside – it is the sidethat along with the hypotenuse forms the angle. From your description, what you have called the Adjacent is actually the Opposite ! The Opposite is actually (in this case) the base of the triangle, so in that case, use sin x = 7/9 =07777. …. so x = sin^-1(0.77777…) or arcsin(0.7777….) – whichever you normally use, giving x = 51.05755… degrees – round off as you would normally do.

Source(s): Retired Maths Teacher
• sin(x) = 7/9 = 0.77778

x = 51.05 degrees

——————————-

Also Check This  I need a metaphor for beautiful eyes…?