Wings on race cars push them into the track. The increased normal force makes large friction forces possible. At one Formula One racetrack, cars turn around a half-circle with diameter 190m at 68m/s .
For a 610 kg vehicle, the approximate minimum static friction force to complete this turn is?
1 Answer
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In turning thru a circular arc the Centripetal force requirement must be met by the static friction force on tires or car will slip (along radius of curve).
D = 190 m
R = 190/2 = 95 m
Fc = mV²/R = 610(68)²/95 = 29,691 ≈ 29,700 N = total static friction force (all 4 tires) or ≈ 7430 N per tire ANS
