1 Answer

For a given angle θ from the horizontal:
Vertical component of velocity will be v.sinθ
Horizontal component will be v.cosθ
Time taken to reach maximum height:
v = u + at
a = g
v = 0
u = v.sinθ
0 = v.sinθ – gt
t = v.sinθ/g
Distance covered in time t
= v.cosθ.v.sinθ / g
= v²sinθcosθ / g
= v²sin(2θ) / (2g)
The distance will be maximum when sin(2θ) = 1
2θ = 90°
θ = 45°