# For an electron moving in a direction opposite to the electric field…?

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a) its potential energy increases and its electric potential decreases.

b) its potential energy increases and its electric potential increases.

c) its potential energy decreases and its electric potential increases.

d) its potential energy decreases and its electric potential decreases.

What is the answer and why? Any help is truly appreciated!

• c) its potential energy decreases and its electric potential increases.

Remember, electrons are negatively charged.

Electric field and electric potential (voltage) are defined to be “positive centric” for hypothetical positive charge. Hence electrons behave opposite.

Positive charges tend to go “downhill” in an electric field, thus decreasing in voltage and decreasing in electric potential energy.

Electrons tend to go “uphill” in an electric field, just like this one, thus (because voltage is a function of space and not the particle going through the set-up), voltage increases just like it does for a positive charge.

Whatever change there may be in voltage, multiply by the charge of an electron to get the corresponding change in electric potential energy, which is hence negative.

• Your concept is incorrect. A static cost merely sitting there is waiting to independently produce an electric container. in case you have a dipole (advantageous and damaging ends) you will then have a “closed” electric container (starts off on the advantageous, ends on the damaging cost.) A battery acts like a dipole and produces cutting-edge. Is a battery a moving magnet by applying any danger? A changing magnetic container is likewise waiting to supply a changing electric container, nevertheless the present output heavily isn’t stable. that’s regularly going on as Alternating cutting-edge. And by applying the way, the sector lines at the instant are not appropriate by applying any danger to the form of the circuit. Electrons “choose for” to pass that way basically by fact its extra straightforward (larger conductivity)

• I’m Gonna GUESS B so . . it’s probably c

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