a) 0.21 M HCl
ph=
b)2.8×10^−2 M HNO3.
ph=
c)a solution that is 5.3×10^−2 M in HBr and 2.0×10−2 M in HNO3.
ph=
d)a solution that is 0.680%HNO3 by mass (Assume a density of 1.01g/ml for the solution.)
ph=
can you please explain in detail how you got the answers? Thanks
3 Answers
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a) 0.21 M HCl
[H+] = 0.21M
pH = -log(0.21) = 0.678
pOH = 14-0.678 = 13.322
[OH-] = 10^-13.22 = 4.76 x 10^-14M
b)2.8×10^−2 M HNO3.
[H+] = 2.8E-2
pH = -log(2.8E-2) = 1.55
pOH = 14-1.55 = 12.44
[OH-] = 10^-12.44 = 3.57 x 10^-13M
c)a solution that is 5.3×10^−2 M in HBr and 2.0×10−2 M in HNO3.
[H+] = 5.3E-2 + 2.0E-2 = 7.3E-2
pH = -log(7.3E-2) = 1.14
pOH = 14-1.14 = 12.86
[OH-] = 10^-12.86 = 1.38 x 10^-13M
d)a solution that is 0.680%HNO3 by mass (Assume a density of 1.01g/ml for the solution.)
1L of solution has a mass of 1010g.
The mass of HNO3 in 1010g of solution = 1010g x .00680 = 6.87gHNO3
6.87g x [1mole / 63g ] = 0.109moles in 1L = 0.109M
[H+] = 0.109M
pH = -log(0.109) = 0.963
pOH = 14-.963 = 13.037
[OH-] = 10^-13.037 = 9.17 x 10^-14M
Hope this helps.
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strategies-blowing this might properly be a tip: PH > 7 is a difficulty-loose answer PH < 7 is an acidic answer PH=7 is a autonomous answer OH is a base H30 = H+ is acid you’re in a position to do the above themes of this hint and there might desire to be a table on your e book with the Ka and Kb values so which you would be able to parent this out.
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a answer has a pOH of two.00. what’s the [H+] and [OH-]? a million.0 x 10-11, a million.0 x 10-3 a million.0 x 10-12, a million.0 x 10-2 a million.0 x 10-7, a million.0 x 10-7 a million.0 x 10-2, a million.0 x 10-12 a million.0 x 10-10, a million.0 x 10-4
