Home / Questions / Given that Ka for HF is 6.3 × 10-4 at 25 °C, what is the value of Kb for F– at 25 °C?

Given that Ka for HF is 6.3 × 10-4 at 25 °C, what is the value of Kb for F– at 25 °C?

November 28, 2022 0

and the second question is

Given that Kb for CH3NH2 is 5.0 × 10-4 at 25 °C, what is the value of Ka for CH3NH3 at 25 °C?

I’ll pick best answer to whoever helps. Thanks. 🙂

Ka x Kb = Kw

Question 1: Kb = Kw/Ka

Kb = 1×10^-14/6.3×10^-4

Question 2: Ka = Kw/Kb

Ka = 1×10^-14/5×10^-4
Richard Dale and Dave Hopkins posted the same question. You should read their answers side by side.
Potato. Potato’s are always the answer.