Given that Ka for HF is 6.3 × 10-4 at 25 °C, what is the value of Kb for F– at 25 °C?

NetherCraft 0

and the second question is

Given that Kb for CH3NH2 is 5.0 × 10-4 at 25 °C, what is the value of Ka for CH3NH3 at 25 °C?

I’ll pick best answer to whoever helps. Thanks. 🙂

3 Answers

  • Ka x Kb = Kw

    Question 1: Kb = Kw/Ka

    Kb = 1×10^-14/6.3×10^-4

    Question 2: Ka = Kw/Kb

    Ka = 1×10^-14/5×10^-4

  • Richard Dale and Dave Hopkins posted the same question. You should read their answers side by side.

  • Potato. Potato’s are always the answer.

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