and the second question is
Given that Kb for CH3NH2 is 5.0 × 10-4 at 25 °C, what is the value of Ka for CH3NH3 at 25 °C?
I’ll pick best answer to whoever helps. Thanks. 🙂
Ka x Kb = Kw
Question 1: Kb = Kw/Ka
Kb = 1×10^-14/6.3×10^-4
Question 2: Ka = Kw/Kb
Ka = 1×10^-14/5×10^-4
Richard Dale and Dave Hopkins posted the same question. You should read their answers side by side.
Potato. Potato’s are always the answer.