A 1.261 g sample burns in a calorimeter (heat capacity of 1262 J/°C) that contains 1.225 kg of water. What is the temperature change (in °C)?
1 Answer
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(1.261 g C6H5COOH) / (122.1213 g C6H5COOH/mol) x (3227 kJ/mol) = 33.32135 kJ =
33321.35 J produced
(4.184 J/g·°C) x (1225 g) = 5125.4 J/°C for the water
(5125.4 J/°C water) + (1262 J/°C calorimeter) = 6387.4 J/°C total
(33321.35 J) / (6387.4 J/°C) = 5.217°C change
