A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0 m/seconds square
How far does the elevator move while accelerating to full speed from rest?
How long does it take to make the complete trip from bottom to top?
1 Answer
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time it takes to get to 5 m/s
velocity=accel*time 5m/s= 1m/s/s*time time=5 sec
distance=1/2 a t^2 = 1/2(1) 5^2 = 12.5 m/s
It would take 12.5 meters to go from zero to 5 m/s.
I would assume you need 5 seconds to take it from 0 to 5 m/s and it would take the same amount of time to go from 5 m/s to zero.
that would be 25 meters. for the remaining 175 meters, we find the distance by dividing 175 meters in to 5 m/s;
175 meters/ 5 m/s= 35 seconds
Because it took 5 seconds to accel and decell, then the total time would be;
35 sec+ 5 sec+ 5 sec= 45 sec
