How many atoms of phosphorus are in 8.80 moles of copper(II) phosphate?

NetherCraft 0

4 Answers

  • this is Cu3(PO4)2 and each mole has 3 mol of Cu atoms

    so

    8.80 mol compound * 3 mol Cu / mol compound * 6.022E23 atm/mol = 1.60E25 atoms Cu

    When you get a good response,

    please consider giving a best answer.

    This is the only reward we get.

    You may have to wait an hour to award BA.

  • Each mole of Cu3(PO4)2 has 2 moles of P in it. So:

    8.80 mol Cu3(PO4)2 X (2 mol P / 1 mol Cu3(PO4)2) X 6.022X10^23 atoms/1 mol = 1.06X10^25 P atoms.

  • copper(II)phosphate is Ca3(PO4)2

    Hence in one molecule of Ca3(PO4)2 there are two(2) atoms of Phosphorus.

    Remember the Avogadro No. 1 mole = 6.022 x 10^23 molecules

    Hence 8.80 moles there are

    8.80 x 6.022 x 10^23 x 2 = 1.06 x 10^25 atoms of phosphorus.

  • Cu3(PO4)2

    8.8 mol Cu => n=N/Na

    N = n*Na = 8.8*3*(6.022*10^23) = 3*5.3*10^24 atoms = 1.6*10^25 atoms

Also Check This  Gas station?

Leave a Reply

Your email address will not be published. Required fields are marked *