How many grams of calcium nitrate, Ca(NO3)2, contains 24 grams of oxygen atoms?

NetherCraft 0

how would you solve this?

2 Answers

  • Step 1: Find the molar mass of Ca(NO3)2 and O.

    Ca(NO3)2 = 40.08 + 2(14.01) + 6(16) = 164.10g

    O = 16g

    Step 2: Find the mole ratio between Ca(NO3)2 and O

    There is 1 mole of Ca(NO3)2 to 6 moles of O, so the ratio is 1 to 6

    Step 3: Calculate grams of Ca(NO3)2.

    24g O (1 mol O / 16g O) (1 mol Ca(NO3)2 / 6 mol O) (164.1g Ca(NO3)2 / 1 mol Ca(NO3)2) = 41g Ca(NO3)2

    Bill

  • Don’t be lazy – I’m not going to work it out for you! You want the molar mass of caclcium nitrate, then the nolar mass of oxygen in it (6 x 16) , then reduce it in proportion.

    Source(s): me!

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