In the figure, let V=12.0V and C1=C2=C3=32.6μF. How much energy is stored in the capacitor network?
1 Answer
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Total capacitance of network (s – series, p – parallel)
C2 s C3 = 32.6μF s 32.6μF = 32.6μF / 2 = 16.3μF
C_T = C1 p C2s3 = 32.6μF p 16.3μF = 48.9μF
Energy stored in the capacitor network.
U = ½ Q² / C = ½ Q V = ½ C V²
U = ½ C_T V² = ½ * 48.9μF (12.0V)² = 3.52 mJ
