I know that x^2-16 is a perfect square but +16 will not factor. I believe there is a formula similar to the cube root formula but not sure? Maybe I am just over thinking this. Thanks for the help
9 Answers
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(x+4)(x-4)
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X 2 16
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Factor X 2-16
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RE:
How to factor x^2+16?
I know that x^2-16 is a perfect square but +16 will not factor. I believe there is a formula similar to the cube root formula but not sure? Maybe I am just over thinking this. Thanks for the help
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Use the quadratic equation even though you will get soem imaginary number
Remember when using the formula
a=1
b=0
c=16
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There are no REAL distinct roots for that. If you were to subtract 16, you would be taking a negative square root, which is not allowed. If you did, you would be getting into a branch of mathematics called imaginary numbers (i). For your purposes, there are no roots.
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you need to think what time +16 and add or subtract 0
(4)(4)= 16
+4+4= 8
This is case they will be give you image number. That’s not real number.
(x^2-16)
it is work because
(-4)(4)= -16
-4+4=0
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this is a trick question. The answer is that it can’t factor further so it is undefined.
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If you are aware of i
where i =sqrt(-1)
then the roots are (x+4i) and (x-4i)