# How to factor x^2+16?

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I know that x^2-16 is a perfect square but +16 will not factor. I believe there is a formula similar to the cube root formula but not sure? Maybe I am just over thinking this. Thanks for the help

• (x+4)(x-4)

• X 2 16

• Factor X 2-16

RE:

How to factor x^2+16?

I know that x^2-16 is a perfect square but +16 will not factor. I believe there is a formula similar to the cube root formula but not sure? Maybe I am just over thinking this. Thanks for the help

• Use the quadratic equation even though you will get soem imaginary number

Remember when using the formula

a=1

b=0

c=16

• There are no REAL distinct roots for that. If you were to subtract 16, you would be taking a negative square root, which is not allowed. If you did, you would be getting into a branch of mathematics called imaginary numbers (i). For your purposes, there are no roots.

• you need to think what time +16 and add or subtract 0

(4)(4)= 16

+4+4= 8

This is case they will be give you image number. That’s not real number.

(x^2-16)

it is work because

(-4)(4)= -16

-4+4=0

• this is a trick question. The answer is that it can’t factor further so it is undefined.

• If you are aware of i

where i =sqrt(-1)

then the roots are (x+4i) and (x-4i)

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