The airplane is traveling 900km/h in a direction 38.5 degree west of north.
The answer is north is 704 km/h and west is 560 km/h.
Please can u show me how to solve for it
So imagine a cartesian coordinate system where +z is north -z south, -x west, +x east.
38.5 deg west of north means that the angle between the velocity and the +z axis is 38.5 degrees.
We simply use the sin and cos functions to find this.
We know that
sin(deg) = opposite/hypoteneuse
We will use sin to find the westernly direction and cos to find the northernly direction due to the fact that 38.5 deg is measured from the z axis.
900*sin(38.5) = 560
900*cos(38.5) = 704
You would use trig to solve this problem:sin(38.5)*900=560 and cos(38.5)*900=704.