Use the result from Part C to find the two solutions to the equation .
The equation 2x^23x5=0
a=2, b=3, c=5
3+suareroot 3^24(2)(5)/2(2) The program asks this ?
Enter the two solutions separated by a comma. The answer I came up with so far is x=3+squareroot 49/4 and x=3+squareroot7/4 but I don’t think this is right totally please help I need to find the 2 solutions
2 Answers

answer is x=(3 + 7)/4 and (37)/4
x = 10/4 = 5/2 and 4/4 = 1

(b +/ (b^24ac)^0.5)/2a
= (3 +/ (94x2x5)^0.5)/4
= (3 +/ 7)/4
=2.5, 1