If 30.0g of MgSO4*7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

NetherCraft 0

3 Answers

  • Anhydrous magnesium sulfate would be the mass of magnesium sulfate without the water of crystallization.

    Hence

    Mass of magnesium sulphate = 24 + 32 + 16 X 4

    = 120

    Mass of hydrated magnesium sulphate

    = 24 + 32 + 16 X 4 + 7 X 18

    = 246

    Mass of anhydrous magnesium sulfate

    = 120/246 X 30

    = 14.63414634g

    = 14.6g (3 significant figures)

    Hope you have had all your queries cleared.

  • RMM of the whole compound = 246 g

    Rmm of 7H2O = 126g

    so RMM of anhydrous sulfate = 120g

    mass of anhydrous sulfate = (120/246) * 30g = 14.63g.

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