If 31.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

NetherCraft 0

Express your answer to three significant figures.

If you could also thoroughly explain how to get the answer, that would be great!

1 Answer

  • Molar mass of MgSO4.7H2O =246.52 g/mol

    Now 246.52 g/mol of MgSO4.7H2O contains 7×18 i.e. 126 g of H2O

    So 31.0 g of MgSO4.7H2O will contain 31.0 x 126/246.52 = 15.8 g H2O

    Thus weight of anhydrous MgSO4 = 31.0 – 15.8 = 15.2 g

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