If 9 is subtracted from the sum of two consecutive even integers, the result is 3 more than the larger of the?

2 Answers

• The first answer fails to consider that the problem says the sum of two consecutive

  EVEN integers, so their difference is 2. Call them N and N+2.

  Their sum is N + N+2

  If you subtract 9 from the sum, that’s 2N + 2 – 9 or 2N – 7 and that equals

  3 more than the larger, or N + 2 + 3 or N + 5.

  If they are equal we can say: 2N – 7 = N + 5

  Add 7 to both sides and get: 2N = N + 12

  Subtract N from both sides: N = 12 and N + 2 = 14.

  The integers are 12 and 14. They are two consecutive even integers.

  To check, add them and subtract 9; we get 17, which is 3 more than 14.

  So our answer of 12 and 14 is correct.

  Source(s): high school algebra

• Y+(Y-1) -9 = Y+3

  This is stating your question.

  I don’t think I need to solve it.

  It is very easy from this point.