If f(x) = 2x^3 Ax^2 Bx – 5 and if f(2) = 3 and f(2) = 37 what is the value of A B?
1 Answer

Use the values of x in f(x)
f(x) = 2x^3+ Ax^2 +Bx – 5 , so
f(2) = 2(2)^3+ A(2)^2 + B(2) – 5 and simplify to 2A + B = 4 and
f(2)= 2(2)^3+ A(2)^2 + B(2) – 5 and simplify to 2A – B = 25
Now will you solve these and find A and B?