If f(x) = 2x^3 Ax^2 Bx – 5 and if f(2) = 3 and f(-2) = -37 what is the value of A B?

1 Answer

• Use the values of x in f(x)

  f(x) = 2x^3+ Ax^2 +Bx – 5 , so

  f(2) = 2(2)^3+ A(2)^2 + B(2) – 5 and simplify to 2A + B = -4 and

  f(-2)= 2(-2)^3+ A(-2)^2 + B(-2) – 5 and simplify to 2A – B = 25

  Now will you solve these and find A and B?