Looking down from a stationary tree branch, a merry-go-round spins in a counterclockwise?

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Looking down from a stationary tree branch, a merry-go-round spins in a counterclockwise direction with an angular velocity of 1 radian per second. a squirrel of mass 0.2 kg sis on the outer rim of the merry-go-round, at a radius of 2.0 meters.

a) What is the magnitude and direction of the vector omega?

b) What is the magnitude and direction of the Coriolis pseudo-force as felt by the squirrel? (equation: -2m(omega x v_r))

c)What is the magnitude and direction of the centrifugal pseudo-force as felt by the squirrel? (equation: -m(omegax(omegaxr_r))

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1 Answer

  • (a) omega = 1 rad/s, direction = upward

    (b) There is no Coriolis force so long as the squirrel is not trying to march inward or outward.

    (c) F = (0.2 kg)(1 s^(-1))^2 (2.0 m) = 0.4 N


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