A gas is compressed by an adiabatic process that decreases its volume by a factor of 2.
In this process, the pressure:
– increases by a factor of 2.
– does not change.
– increases by a factor of more than 2.
– increases by a factor of less than 2.
1 Answer

For an adiabatic process, the product pV^γ remains constant, so p1V1^γ = p2V2^γ, and
p2/p1 = (V1/V2)^γ
If V2 = 1/2 V1, then
p2/p1 = 2^γ
Since γ = cp/cv > 1, the pressure increases by a factor of more than 2.