N2(g) effuses at a rate that is ______ times that of Xe(g) under the same conditions.?

1 Answer

  • For two gases with molar masses M₁ and M₂, the relative rate of effusion is

    (R₁ / R₂) = √(M₂ / M₁)

    R₁ = rate of effusion of N₂

    R₂ = rate of effusion of Xe

    M₁ = molar mass N₂ = 28.014 g/mol

    M₂ = molar mass Xe = 131.293 g/mol

    (R₁ / R₂) = √(131.293 / 28.014) = 2.16

    I arbitrarily wrote the answer to 3 sig figs. I’m not sure how many sig figs you need for your answer.

Leave a Comment