Physics Question- Lightbulb, Resistance, Power,!?

NetherCraft 0

Here is the question:

The corroded contacts in a lightbulb socket have 7.6 Omega total resistance. How much actual power is dissipated by a 110 W (120 V) lightbulb screwed into this socket?

Answer is in P=____W


1 Answer

  • resistance of bulb:

    110 = (120)² /R

    R = 130.9 ohms

    current is 120/(R+7.6) = 0.866A

    P = I²R = 98.3 W

    This assumes the bulb resistance does not change when operated at lower voltage/current.

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