Thanks for the answer
4 Answers

(x1)^(3)=y
Take the cube root of each side of the equation to setup the solution for x.
(x1)^(3*(1)/(3))=(y)^((1)/(3))
Remove the perfect root factor (x1) under the radical to solve for x.
(x1)=(y)^((1)/(3))
Remove the parentheses around the expression x1.
x1=(y)^((1)/(3))
Expand the exponent ((1)/(3)) to the expression.
x1=(y^((1)/(3)))
Remove the parentheses around the expression y^((1)/(3)).
x1=y^((1)/(3))
Since 1 does not contain the variable to solve for, move it to the righthand side of the equation by adding 1 to both sides.
x=1+y^((1)/(3))
Move all terms not containing x to the righthand side of the equation.
x=y^((1)/(3))+1

( x – 1 ) Â³ = y
( x – 1 ) = y^(1/3)
x = y^(1/3) + 1

(x – 1)^3 = y
x – 1 = y^1/3)
x = y^(1/3) + 1

(x – 1)^3 = y
x – 1 = y^(1/3)
x = y^(1/3) + 1